Solving Linear Equation Practice Question

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Algebra equation r +3 = 9 -2r
Question 2
Solve the following linear equation:

Answer

Select and check your answer...
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A. +3
B. -3
C. -2
D. 2
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Step by Step Solution 

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Step 1
To solve the linear equation, add -3 to both sides of the equation to remove +3. The equation becomes:
                            r +3 -3 = 9 -2r -3

Now, on the Left Hand Side (LHS) of the equation, +3 and -3 cancels off.  We are left with :  
                                r = 9 -2r -3 
Algebra equations r = 9 -2r -3
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Step 2
Keeping the objective in mind, r = ?, we need to remove -2r on the Right Hand Side (RHS) of the equation. Hence, adding +2r to both sides:
 
                            r +2r = 9 -2r +2r -3

Now, on the RHS, -2r and +2r cancels off.  We are left with:
  
                                r +2r = 9 -3 
Algebra equations r +2r = 9 -3
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Step 3
Now, we can simplifying the terms on the LHS by adding r and 2r. This gives 3r.
 
                      3r = 9 -3

Similarly, simplifying the terms in the RHS adding 9 and -3. This gives 6  

                       3r = 6  
Algebra equations 3r = 6
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Step 4
Realize that to get r = ?, we need to remove 3 from 3r. To do so, we can divide both sides by 3 as shown in the picture.



Now, on the LHS, the we 3 divides by 3 cancels off.
So, we are left with r = 6/3.

Divide '3r = 6' with 3 on both sides
r = 6/3
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Step 5
Now, on the RHS, 6/3 gives 2. Finally, we have r = 2.

So, the answer is D.
Answer is r = 2
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